document.write( "Question 284348: The length of a rectangle is 6ft longer than its width.
\n" ); document.write( "If the perimeter of the rectangle is 40ft ,what is its area. \n" ); document.write( "

Algebra.Com's Answer #206384 by brucewill(101) $\"\"$ $\"About$

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First, we need to compute the length of each side:\r
\n" ); document.write( "\n" ); document.write( "Let x = Width
\n" ); document.write( "Therefore x+6 = Length\r
\n" ); document.write( "\n" ); document.write( " $\"2x+%2B+2%28x%2B6%29+=+40\"$
\n" ); document.write( "===
\n" ); document.write( " $\"2x+%2B+2x+%2B+12+=+40\"$
\n" ); document.write( "===
\n" ); document.write( " $\"4x+=+28\"$
\n" ); document.write( "===
\n" ); document.write( "x = 7 (width), therefore 13 is the length.
\n" ); document.write( "===
\n" ); document.write( "Area is Width * Height: $\"7%2A13+=+highlight%2891%29\"$ \n" ); document.write( "

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