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document.write( "So the last digits go in blocks of 4 like this: 7,9,3,1\r\n" );
document.write( " \r\n" );
document.write( "So we just divide 2009 by 4\r\n" );
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document.write( " 502 \r\n" );
document.write( " -----\r\n" );
document.write( "4)2009\r\n" );
document.write( " 20\r\n" );
document.write( " --\r\n" );
document.write( " 009\r\n" );
document.write( " 008\r\n" );
document.write( " ---\r\n" );
document.write( " 1 \r\n" );
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document.write( "That division tells us the last digits go \r\n" );
document.write( "through the cycle 7,9,3,1 502 times and the \r\n" );
document.write( "remainder, being 1, means that they end up \r\n" );
document.write( "on the first of the 503rd cycle and must \r\n" );
document.write( "therefore be a 7.\r\n" );
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document.write( "Edwin
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