document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284232>Question 284232</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 hikers start at opposie ends of the trail and walk towards each other. the trail is 36 miles long and they meet in 4 hours. if one hiker is twice as fast as the other, find both hiking speeds.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206291 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of one hiker be x\r<BR>\n" );
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document.write( "the other's speed = 2x\r<BR>\n" );
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document.write( "distance traveled in 4 hours = 4x miles \r<BR>\n" );
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document.write( "The other traveled for 8x miles\r<BR>\n" );
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document.write( "4x+8x=36\r<BR>\n" );
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document.write( "12x=36\r<BR>\n" );
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document.write( "x= 3 mph\r<BR>\n" );
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document.write( "the other's speed = 6 mph </SPAN>\n" );
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