document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284049>Question 284049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve this system of equations algebraically :<BR>\n" );
document.write( "x^2+y^2=25, 4y=3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206284 by </B><A HREF=/tutors/aboutme.mpl?userid=hello_me><B>hello_me(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hello_me><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ok so we have our two equations. so why not sub in y? so we have 4y=3x<BR>\n" );
document.write( "so y=3x/4<BR>\n" );
document.write( "when we sub that in we get x^2+9x^2/16 =25<BR>\n" );
document.write( "now to get rid of our fraction mulitply ecverything by 16 <BR>\n" );
document.write( "and we get<BR>\n" );
document.write( "16x^2+9x^2 = 400<BR>\n" );
document.write( "we then get 25x^2 = 400<BR>\n" );
document.write( "so x^2 = 16<BR>\n" );
document.write( "there fore x can equal 4 or -4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );