document.write( "Question 284246: with the current, joe can row a canoe 3 miles in 12 mins. Against the current, he requires 18 minutes to row same distance. HOw fast does joe row in still water, and how fast is the current? \n" ); document.write( "

Algebra.Com's Answer #206243 by stanbon(75887) $\"\"$ $\"About$

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with the current, joe can row a canoe 3 miles in 12 mins. Against the current, he requires 18 minutes to row same distance. HOw fast does joe row in still water, and how fast is the current?
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\n" ); document.write( "With Current:
\n" ); document.write( "distance = 3 miles ; time = 1/5 hr ; rate = 3/(1/5) = 15 mph
\n" ); document.write( "-------------------------------------------------------
\n" ); document.write( "Against Current:
\n" ); document.write( "distance = 3 miles ; time = 3/5 hr ; rate = 3/(3/5) = 5 mph
\n" ); document.write( "-------------------------------------------------------
\n" ); document.write( "Equations:
\n" ); document.write( "b + c = 15 mph
\n" ); document.write( "b - c = 5 mph
\n" ); document.write( "----------------------
\n" ); document.write( "2b = 20
\n" ); document.write( "b = 10 mph (speed of the boat in still water)
\n" ); document.write( "-------------------------
\n" ); document.write( "Substitute to solve for \"c\":
\n" ); document.write( "10 + c = 15
\n" ); document.write( "c = 5 mph (speed of the current)
\n" ); document.write( "===================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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