document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284175>Question 284175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x-40=6y<BR>\n" );
document.write( "2y=8-3x by the addition method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206210 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 'addition' method for solving systems of linear equations is also known as the 'elimination' method.<BR>\n" );
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document.write( "First, get the equations into standard form:  Ax + By = C<BR>\n" );
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document.write( "5x -40 = 6y<BR>\n" );
document.write( "5x - 6y = 40  :: (EQ 1)<BR>\n" );
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document.write( "2y = 8 - 3x<BR>\n" );
document.write( "3x + 2y = 8  :: (EQ 2)<BR>\n" );
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document.write( "If we multiply EQ 2 by 3, the two equations will be in shape to eliminate the 'y' term.<BR>\n" );
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document.write( "5x -6y = 40  :: (EQ 1)<BR>\n" );
document.write( "9x + 6y = 24  :: (EQ 2 * 3)<BR>\n" );
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document.write( "adding...<BR>\n" );
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document.write( "14x = 64<BR>\n" );
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document.write( "x = 64/14 = 32/7<BR>\n" );
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document.write( "substitute x = 32/7 in EQ 1 to find y<BR>\n" );
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document.write( "5(32/7) -6y = 40<BR>\n" );
document.write( "160/7 -6y = 40<BR>\n" );
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document.write( "multiply both sides by 7 to remove the denominator<BR>\n" );
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document.write( "160 -42y = 280<BR>\n" );
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document.write( "subtract 120 from both sides<BR>\n" );
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document.write( "-42y = 120<BR>\n" );
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document.write( "divide both sides by -42<BR>\n" );
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document.write( "y = -120/42 = -60/21<BR>\n" );
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document.write( "So, we think the intersection of the two lines will be:  (32/7, -60/21) = (4 4/7, -2 6/7)<BR>\n" );
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document.write( "Graphing is good way to check.<BR>\n" );
document.write( "The slope-intercept form is a good way to compute the lines:  y = mx+b.<BR>\n" );
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document.write( "5x-40=6y<BR>\n" );
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document.write( "6y = 5x -40<BR>\n" );
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document.write( "divide by 6<BR>\n" );
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document.write( "y = 5/6x - 40/6<BR>\n" );
document.write( "y = 5/6x - 20/3<BR>\n" );
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document.write( "2y=8-3x<BR>\n" );
document.write( "2y = -3x + 8<BR>\n" );
document.write( "y = -3/2x + 4<BR>\n" );
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