document.write( "Question 284179: Could someone please help me with this problem? Use the formula N = Ie^kt, where N is the number of items in terms of the initial population I, at time T, and k is the growth constant equal to the percent of growth per unit of time. A certain radioactive isotope decays at a rate of 0.275% annually. Determine the half-life of this isotope to the nearest year. \n" ); document.write( "
Algebra.Com's Answer #206201 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Use the formula N = Ie^kt, where N is the number of items in terms of the initial population I, at time T, and k is the growth constant equal to the percent of growth per unit of time. A certain radioactive isotope decays at a rate of 0.275% annually. Determine the half-life of this isotope to the nearest year. \n" ); document.write( "------------------------------- \n" ); document.write( "Note: Since this is a decay function I believe you need a negative \n" ); document.write( "in the exponent. \n" ); document.write( "---------------------- \n" ); document.write( "Substitute and solve for \"t\": \n" ); document.write( "(I/2) = I*e^(-0.275t) \n" ); document.write( "(1/2) = e^(-0.275t) \n" ); document.write( "--- \n" ); document.write( "Take the natural log to get: \n" ); document.write( "-0.275t = ln(1/2) \n" ); document.write( "t = -0.6931../-0.275 \n" ); document.write( "t = 2.52 years \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |