document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4527>Question 4527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the inverse of the function f(x) = 4x^3 - 2 and graph f and f^(-1) on the same pair of axis </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2062 by </B><A HREF=/tutors/aboutme.mpl?userid=pushpaharan><B>pushpaharan(47)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pushpaharan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to find the inverse change x->y and y->x<BR>\n" );
document.write( "y= 4x^3 - 2 will change into<BR>\n" );
document.write( "x=4y^3-2<BR>\n" );
document.write( "4y^3 = x+2<BR>\n" );
document.write( "y^3 =(x+2)/4<BR>\n" );
document.write( "y = ((x+2)/4) ^ (1/3)\r<BR>\n" );
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document.write( "otherwise follow reverse order of order of operation<BR>\n" );
document.write( "y= 4x^3 - 2 here first exponent by 3 -> multiply by 4 -> subtact 4<BR>\n" );
document.write( "to find inverse<BR>\n" );
document.write( "first add by 4 -> divide by 4 -> exponet by 1/3\r<BR>\n" );
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document.write( "graphing you have to do it.. i cannot explain here </SPAN>\n" );
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