document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284155>Question 284155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I find the values of a & b that would make the quadrilateral a parallelogram:<BR>\n" );
document.write( "2a+6,6b-a,3a-10,5a+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206185 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we would need sets of sides that are equal.<BR>\n" );
document.write( "2a+6=3a-10<BR>\n" );
document.write( "6b-a=5a+1<BR>\n" );
document.write( "a = 16,   b = 97/6<BR>\n" );
document.write( "they don't work out so well<BR>\n" );
document.write( "but neither do<BR>\n" );
document.write( "2a+6= 6b-a,<BR>\n" );
document.write( "5a+1=3a-10<BR>\n" );
document.write( "a = -11/2,   b = -7/4\r<BR>\n" );
document.write( "\n" );
document.write( " 2a+6=5a+1,<BR>\n" );
document.write( " 6b-a=3a-10<BR>\n" );
document.write( "this is all that good either but <BR>\n" );
document.write( "a = 5/3,   b = -5/9<BR>\n" );
document.write( "We can't have negative values so it must be the first grouping </SPAN>\n" );
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