document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=284127>Question 284127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Millicent began the journey at 6 am at 50 kilometers per hour.  Beauregard began to chase her at 10 am at 60 kph.  What time was it when Beauregard got within 40 kilometers of Millicent </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206177 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m=50*(t+4)<BR>\n" );
document.write( "b=60*(t)<BR>\n" );
document.write( "m-b=40<BR>\n" );
document.write( "If they were trying to meet it would be 10t=200 t=20 20 hours<BR>\n" );
document.write( "M went 200 miles from 6 am to 10 am.\r<BR>\n" );
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document.write( "in 20 hours for m 1000 from 6 am at 2 am the next day<BR>\n" );
document.write( "in 16 hours for b 960 <BR>\n" );
document.write( "10 am +16 hours =2 am the next day they were within 40 k of each other.<BR>\n" );
document.write( "They finally would meet 4 more hours later at 6am the second day<BR>\n" );
document.write( "  <BR>\n" );
document.write( "b gained on m at 10 kph </SPAN>\n" );
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