document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34337>Question 34337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mixture of 30 lbs. of candy sells for $1.10 a pound. The mixture consists of chocolates worth $1.50 a pound and chocolates worth 90¢ a pound. How many pounds of each kind were used to make the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20617 by </B><A HREF=/tutors/aboutme.mpl?userid=fanism><B>fanism(39)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fanism><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20617\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the chocolates worth $1.50 a pound <BR>\n" );
document.write( "and let y be the chocolates worth 90¢ a pound.\r<BR>\n" );
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document.write( "1.5x + 0.9y = 30(1.1) -- eq1<BR>\n" );
document.write( "x + y = 30 --> x = 30 - y -- eq2<BR>\n" );
document.write( "sub eq2 into eq1, u get\r<BR>\n" );
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document.write( "1.5(30-y) + 0.9y = 33<BR>\n" );
document.write( "12 = 0.6y<BR>\n" );
document.write( "y = 20\r<BR>\n" );
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document.write( "put back into eq2,<BR>\n" );
document.write( "x + 20 = 30<BR>\n" );
document.write( "x = 10 </SPAN>\n" );
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