document.write( "Question 31748: Question: Evaluate: 1n(1/5sqrt e)\r
\n" ); document.write( "\n" ); document.write( "(A) 1/5
\n" ); document.write( "(B) -1/5
\n" ); document.write( "(C) -5
\n" ); document.write( "(D) 5\r
\n" ); document.write( "\n" ); document.write( "Thank you! \n" ); document.write( "
Algebra.Com's Answer #20616 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Question: Evaluate: I SUPPOSE YOU MEAN.....PUT BRACKETS TO AVOID CONFUSION....1n((1)/(5sqrt e))=LN(1)-LN(5SQRT(E))=0-LN(5)-LN(E^0.5)
\n" ); document.write( "=-LN(5)-0.5LN(E)=-LN(5)-0.5...CHECK THE PROBLEM FOR PROPER TYPING\r
\n" ); document.write( "\n" ); document.write( "I THINK THE QUESTION IS LN(1/FIFTH ROOT OF E)
\n" ); document.write( "IT IS NOT SQUARE ROOT
\n" ); document.write( "IF NOTHING IS PUT IN V GROOVE OF THE SYMBOL IT IS SQUARE ROOT
\n" ); document.write( "IF 3 IS PUT IN V GROOVE OF THE SYMBOL IT IS CUBE ROOT
\n" ); document.write( "IF 4 IS PUT IN V GROOVE OF THE SYMBOL IT IS FOURTH ROOT
\n" ); document.write( "IF 5 IS PUT IN V GROOVE OF THE SYMBOL IT IS FIFTH ROOT...ETC....
\n" ); document.write( "I HOPE YOU KNOW 5 TH ROOT
\n" ); document.write( "IF 2*2*2*2*2=2^5=32
\n" ); document.write( "WE SAY 5TH.ROOT OF 32 =32^(1/5)= 32^0.2= 2...SO ASSUMING THAT WE GET
\n" ); document.write( "LN(1/FIFTH ROOT OF E)=LN(1/E^(1/5))=-LN(E^(1/5))=-(1/5)LN(E)=-1/5 IS THE ANSWER.
\n" ); document.write( "HENCE B IS THE ANSWER \n" ); document.write( "
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