document.write( "Question 182663: A Man's age this year is three times that of his Son. If in 15 years time the Father will be twice as old as his Son, find their present ages. \n" ); document.write( "
Algebra.Com's Answer #206154 by Cally69(1)![]() ![]() ![]() You can put this solution on YOUR website! Simultaneous Equations\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F = Father S=Son\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F - 3S = 0 (equation 1) \n" ); document.write( "F - 2S = 15 (equation 2)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " F - 3S = 0 \n" ); document.write( "- F - 2S = 15 \n" ); document.write( " \n" ); document.write( " = -1S = -15 => -15/-1 = S = 15 \n" ); document.write( "Eliminate Value (F)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Son = 15 years of age\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F - 3S = 0 => F - 45 = 0 = Value of (F) => 45 - 0 = 45/1 = F = 45\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Father = 45 years of age\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To prove it. \n" ); document.write( " F - 3S = 0 = 45 - 45 = 0 (equation 1) \n" ); document.write( " F - 2S = 15 = 45 - 30 = 15 (equation 2) \n" ); document.write( " |