document.write( "Question 182663: A Man's age this year is three times that of his Son. If in 15 years time the Father will be twice as old as his Son, find their present ages. \n" ); document.write( "
Algebra.Com's Answer #206154 by Cally69(1)\"\" \"About 
You can put this solution on YOUR website!
Simultaneous Equations\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "F = Father S=Son\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "F - 3S = 0 (equation 1)
\n" ); document.write( "F - 2S = 15 (equation 2)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " F - 3S = 0
\n" ); document.write( "- F - 2S = 15
\n" ); document.write( "
\n" ); document.write( " = -1S = -15 => -15/-1 = S = 15
\n" ); document.write( "Eliminate Value (F)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Son = 15 years of age\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "F - 3S = 0 => F - 45 = 0 = Value of (F) => 45 - 0 = 45/1 = F = 45\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Father = 45 years of age\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To prove it.
\n" ); document.write( " F - 3S = 0 = 45 - 45 = 0 (equation 1)
\n" ); document.write( " F - 2S = 15 = 45 - 30 = 15 (equation 2)
\n" ); document.write( "
\n" );