document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283894>Question 283894</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve the following:<BR>\n" );
document.write( "2x = 2 - y<BR>\n" );
document.write( "3x + y = -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206034 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first thing is rearrange the equations so that they are in ax+by=c order<BR>\n" );
document.write( "2x-y=2<BR>\n" );
document.write( "3x+y=-1<BR>\n" );
document.write( "just add the two equations<BR>\n" );
document.write( "5x=1<BR>\n" );
document.write( "x=1/5<BR>\n" );
document.write( "substitute into either equation<BR>\n" );
document.write( "2*1/5-y=2<BR>\n" );
document.write( "2/5-y=2<BR>\n" );
document.write( "subtract2/5 from both sides<BR>\n" );
document.write( "-y=2-2/5<BR>\n" );
document.write( "-y=1 3/5<BR>\n" );
document.write( "y=-1 3/5= -8/5<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );