document.write( "Question 283875: I am having trouble figuring out this math problem. I dont want the answer only how to solve it. 1.James’ Burger and Shakes first opened in 1950 selling hamburgers for $0.25. In 2010, the price of a burger was now $3.25.
\n" ); document.write( "a.On average, how much did the price of a burger increase per year? Show work to receive credit. \r
\n" ); document.write( "\n" ); document.write( "The answer for this one I have already figured out 5 cents increase per year\r
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\n" ); document.write( "\n" ); document.write( "b.Let x represent the number of years after 1950 (e.g. for 1951 then x = 1). What is the cost y of a hamburger when x = 0? THIS ONE I DONT KNOW WHAT FORMULA TO USE TO FIGURE IT OUT....
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Algebra.Com's Answer #206025 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
You are going to write an equation for a straight line
\n" ); document.write( "with the year as x and the cost as y
\n" ); document.write( "x=year-1950
\n" ); document.write( "1950+x, y=.25
\n" ); document.write( "2010+x y=3.25
\n" ); document.write( "x=2010-1950=60 years since 1950
\n" ); document.write( "325-25=300
\n" ); document.write( "300/60=.05 cents per year
\n" ); document.write( "when x=0 the year is 1950 so the hamburger cost .25
\n" ); document.write( "y=.25+.05x your formula not really needed but it works\r
\n" ); document.write( "\n" ); document.write( "y= cost x=years since 1950
\n" ); document.write( "plug in 60 for x and find y=3.25
\n" ); document.write( "plug in 0 for x and get .25 for y\r
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