document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283868>Question 283868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me with this problem? three times one number minus a second number is 8 and the sum of the number is 12. find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #206007 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=206007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> three times one number minus a second number is 8 and the sum of the number is 12. find the numbers.<BR>\n" );
document.write( "------------------------------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "x + y = 12<BR>\n" );
document.write( "3x-y = 8<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "Add the equations and solve for \"x\":<BR>\n" );
document.write( "4x = 20<BR>\n" );
document.write( "x = 5<BR>\n" );
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document.write( "Substitute into x+y=12 and solve for \"y\":<BR>\n" );
document.write( "5+y = 12<BR>\n" );
document.write( "y = 7<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );