document.write( "Question 283802: One positive integer is 5 less than 4 times another. Their product is 21. Find the integers \n" ); document.write( "

Algebra.Com's Answer #205959 by mananth(16946) $\"\"$ $\"About$

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let one integer be x\r
\n" ); document.write( "\n" ); document.write( "four times integer = 4x\r
\n" ); document.write( "\n" ); document.write( "4x-5 is the second number\r
\n" ); document.write( "\n" ); document.write( "x(4x-5)=21\r
\n" ); document.write( "\n" ); document.write( "4x^2-5x-21=0\r
\n" ); document.write( "\n" ); document.write( "4x^2-12x+7x-21=0\r
\n" ); document.write( "\n" ); document.write( "4x(x-3)+7(x-3)=0\r
\n" ); document.write( "\n" ); document.write( "(x-3)(4x+7)=0\r
\n" ); document.write( "\n" ); document.write( "SO x= 3 or -7/4\r
\n" ); document.write( "\n" ); document.write( "but the integer is positive so x=3 \r
\n" ); document.write( "\n" ); document.write( "the other number = 12\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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