document.write( "Question 283765: solve: x+4/x+2-3/x=-(6/x^2+2x) \n" ); document.write( "
Algebra.Com's Answer #205943 by mananth(16946)\"\" \"About 
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x+4/x+2-3/x=-(6/x^2+2x)\r
\n" ); document.write( "\n" ); document.write( "x(x+4) -3(x+2) / x(x+2) = 6 / x(x+2)\r
\n" ); document.write( "\n" ); document.write( "(x^2+4x-3x-6) / x(x+2) = 6/ x(x+2)\r
\n" ); document.write( "\n" ); document.write( "(x^2+x-6)/x(x+2)=6/x(x+2)\r
\n" ); document.write( "\n" ); document.write( "x(x+2)(x^2+x-6)/x(x+2)= 6\r
\n" ); document.write( "\n" ); document.write( "x(x+2) cancel off\r
\n" ); document.write( "\n" ); document.write( "(x^2+x-6)=6\r
\n" ); document.write( "\n" ); document.write( "x^2-x-6-6=0\r
\n" ); document.write( "\n" ); document.write( "x^2-x-12=0\r
\n" ); document.write( "\n" ); document.write( "x^2-4x+3x-12=0\r
\n" ); document.write( "\n" ); document.write( "x(x-4)+1(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "(x-4)(x+1)=0
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