document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283689>Question 283689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rug is 3 feet shorter than it's length. if the area of the rug is 108 square feet, what are the dimensions of the rug?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205942 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length be x\r<BR>\n" );
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document.write( "the width will be x-3\r<BR>\n" );
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document.write( "area of rectangle = L * W\r<BR>\n" );
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document.write( "area = x(x-3)\r<BR>\n" );
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document.write( "108=x^2-3x\r<BR>\n" );
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document.write( "x^2-3x-108=0\r<BR>\n" );
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document.write( "x^2-12x+9x-108=0\r<BR>\n" );
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document.write( "x(x-12)+9(x-12)=0<BR>\n" );
document.write( "(x-12)(x+9)\r<BR>\n" );
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document.write( "x=12 feet is the length of the rug\r<BR>\n" );
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document.write( "12-3 = 9 feet is the width of the rug\r<BR>\n" );
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