document.write( "Question 283738: please help with this problem a 10% acid solution is to be mixed with a 50% acid solution in order to get 120 ml of a 20% acid solution. how many ml of the 10% solution and 50% should be mixed? \n" ); document.write( "
Algebra.Com's Answer #205920 by oberobic(2304)\"\" \"About 
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With solution problems, you need to keep track of the amount of 'pure' stuff.
\n" ); document.write( "You need to end up with 120 ml of a 20% solution, so that is
\n" ); document.write( ".20 * 120 = 24 ml of 'pure' acid
\n" ); document.write( "120-24 = 96 ml of water
\n" ); document.write( ".
\n" ); document.write( "x = volume of 10% acid
\n" ); document.write( "y = volume of 50% acid
\n" ); document.write( ".
\n" ); document.write( "x+y = 120 ml
\n" ); document.write( ".
\n" ); document.write( "It is better to set up the equation with the minimum number of unknowns.
\n" ); document.write( "In this case, we know the 120 ml is required, so we can say:
\n" ); document.write( "x = volume of 10% acid
\n" ); document.write( "120-x = volume of 50% acid
\n" ); document.write( ".
\n" ); document.write( ".1*x + .5(120-x) = .2*120
\n" ); document.write( ".
\n" ); document.write( "multiply both sides of the equation by 10 to get rid of decimals
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\n" ); document.write( "10*(.1*x + .5(120-x)) = 10*(.2*120)
\n" ); document.write( "10*(.1*x) + 10(.5(120-x)) = 10*(.2*120)
\n" ); document.write( "x + 5(120-x) = 2*120
\n" ); document.write( ".
\n" ); document.write( "x + 600 -5x = 240
\n" ); document.write( ".
\n" ); document.write( "-4x = -360
\n" ); document.write( ".
\n" ); document.write( "x = 90
\n" ); document.write( ".
\n" ); document.write( "y = 120-90 = 30
\n" ); document.write( ".
\n" ); document.write( "Checking, how much 'pure' stuff we would have...
\n" ); document.write( ".1*90 = 9 ml
\n" ); document.write( ".5*30 = 15 ml
\n" ); document.write( "9+15 = 24 ml, which is what we needed
\n" ); document.write( ".
\n" ); document.write( "So the answer is:
\n" ); document.write( "90 ml of a 10% solution
\n" ); document.write( "plus 30 ml of a 50% solution
\n" ); document.write( "to produce 120 ml of 20% solution.
\n" ); document.write( ".
\n" ); document.write( "Done
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