document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283701>Question 283701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A movie theater had a certain number of tickets to give away. Five people got the tickets. The first got one-third of the tickets, the second got one-fourth of the tickets, and the third got one-fifth of the tickets. The fourth person got eight tickets, and there were five tickets left for the fifth person. Find the total number of tickets given away.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205882 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A movie theater had a certain number of tickets to give away. Five people got the tickets. The first got one-third of the tickets, the second got one-fourth of the tickets, and the third got one-fifth of the tickets. The fourth person got eight tickets, and there were five tickets left for the fifth person. Find the total number of tickets given away.\r<BR>\n" );
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document.write( "Let the number of tickets available be x\r<BR>\n" );
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document.write( "1/3 x +1/4 x +1/5 x +8+5 =x\r<BR>\n" );
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document.write( "20x+15x+12x / 60 +13 =x\r<BR>\n" );
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document.write( "47x/60 -x+13=0\r<BR>\n" );
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document.write( "47x-60x/60 =-13\r<BR>\n" );
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document.write( "-13x=-780\r<BR>\n" );
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document.write( "x=60 Number of tickets given away </SPAN>\n" );
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