document.write( "Question 283669: (4+5i)(2-3i) \n" ); document.write( "
Algebra.Com's Answer #205853 by PRMath(133)\"\" \"About 
You can put this solution on YOUR website!
(4+5i)(2-3i)\r
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\n" ); document.write( "\n" ); document.write( "Use FOIL (first outside inside last)\r
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\n" ); document.write( "\n" ); document.write( "First: \"4+%2A+2+=+8\"
\n" ); document.write( "Outside: \"4+%2A+%28-3i%29+=+-12i\"
\n" ); document.write( "Inside: \"%285i%29+%2A+2+=+10i\"
\n" ); document.write( "Last: \"5i+%2A+%28-3i%29+=+-15i%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Let's put it all together: \"8+-+12i+%2B+10i+-15i%5E2\"
\n" ); document.write( "Combine like terms: \"8+-2i+-+15i%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "We're not done yet. See the \"-15i%5E2\"?
\n" ); document.write( "Well, \"i%5E2\" = \"-1\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, for \"-15i%5E2\" you really have: \"%28-15%29%28-1%29\" which is: 15\r
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\n" ); document.write( "\n" ); document.write( "THEREFORE... you really have 8 - 2i + 15, which is.....
\n" ); document.write( "23 - 2i\r
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\n" ); document.write( "\n" ); document.write( "See how that worked out? I hope this helps you. :-)
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