document.write( "Question 283588: Graphing a line given its equation in standard form. Graph the line
\n" ); document.write( "4x-3y-12=0
\n" ); document.write( "

Algebra.Com's Answer #205823 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"4x-3y-12=0\" Start with the given equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"4x-3y=12\" Add 12 to both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-3y=12-4x\" Subtract \"4x\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"-3y=-4x%2B12\" Rearrange the terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28-4x%2B12%29%2F%28-3%29\" Divide both sides by \"-3\" to isolate y.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%28%28-4%29%2F%28-3%29%29x%2B%2812%29%2F%28-3%29\" Break up the fraction.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%284%2F3%29x-4\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Looking at \"y=%284%2F3%29x-4\" we can see that the equation is in slope-intercept form \"y=mx%2Bb\" where the slope is \"m=4%2F3\" and the y-intercept is \"b=-4\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since \"b=-4\" this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So we have one point \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now since the slope is comprised of the \"rise\" over the \"run\" this means\r
\n" ); document.write( "\n" ); document.write( "\"slope=rise%2Frun\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, because the slope is \"4%2F3\", this means:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"rise%2Frun=4%2F3\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "which shows us that the rise is 4 and the run is 3. This means that to go from point to point, we can go up 4 and over 3\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So starting at , go up 4 units \r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "and to the right 3 units to get to the next point \r
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now draw a line through these points to graph \"y=%284%2F3%29x-4\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " So this is the graph of \"y=%284%2F3%29x-4\" through the points and
\n" ); document.write( "
\n" );