Algebra.Com's Answer #20581 by venugopalramana(3286)![\"\"](\"/images/stars/stars-13.gif\")  
You can put this solution on YOUR website!
I am suppose to solve this with out a calcutlator:\r
\n" );
document.write( "\n" );
document.write( "
\n" );
document.write( "FIRSTLY DO YOU MEAN 5*SQRT(2)....OR
\n" );
document.write( "FIFTH ROOT OF 2?
\n" );
document.write( "ASSUMING IT IS 5*SQRT(2)..DO AS FOLLOWS
\n" );
document.write( "1.FIND SQRT(2)=1.414..FROM CALCULATOR..STORE IT IN MEMORY
\n" );
document.write( "NOW FIND ITS LOG TO BASE 10 FROM CALCULATOR.RECALLING FROM MEMORY THE VALUE OF 1.414...YOU WILL GET THE ANSWER AS 0.1505\r
\n" );
document.write( "\n" );
document.write( "ON THE OTHER HAND IF IT IS FIFTH ROOT OF 2 ..
\n" );
document.write( "FIND 2^(1/5)=2^0.2.....USING X^Y FUNCTION IN THE CALCULATOR. YOU WILL GET
\n" );
document.write( "2^0.2=1.1487
\n" );
document.write( "AND LOG OF ABOVE NUMBER TO BASE 10 =0.0602
\n" );
document.write( "the sqrt kinda throws me off, i have a tutor who tried to explain it but they were also confused on what exactly to do. here is what we were trying:\r
\n" );
document.write( "\n" );
document.write( " \r
\n" );
document.write( "\n" );
document.write( " \r
\n" );
document.write( "\n" );
document.write( " cancles out\r
\n" );
document.write( "\n" );
document.write( "answere:
\n" );
document.write( " ??????\r
\n" );
document.write( "\n" );
document.write( "we know we are going in the wrong direction with this but are very lost! please help! thanks! \n" );
document.write( " |