document.write( "Question 283560: Please help me with this substitution Method, I need the steps of how I would get to the answer:\r
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document.write( "2x-3y=-25
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document.write( "3x+y=1\r
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document.write( "Thank you for your help. \n" );
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Algebra.Com's Answer #205794 by JenniferTutors(83)![]() ![]() You can put this solution on YOUR website! To solve this problem by substitution method: \n" ); document.write( "2x - 3y = -25 \n" ); document.write( "3x + y = 1\r \n" ); document.write( "\n" ); document.write( "If you notice in the second equation, there is a y by itself (no number attached): \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First, subtract the 3x from the left to the right side of the equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now place the y equals into the first equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now follow order of operations: \n" ); document.write( "Remember: Negative X Negative = Positive \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now add like terms, x's:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To get 11x by itself, add the 3 from the left to the right side of the equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you have the value of x, next place the x value into the first equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next add the 4 from the left to the right side of the equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide by negative 3 to get y by itself, Negative/Negative = Positive: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check both your values, x = -2, y = 7\r \n" ); document.write( "\n" ); document.write( "Place it into either equation I placed it into the first, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |