document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283560>Question 283560</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this substitution Method, I need the steps of how I would get to the answer:\r<BR>\n" );
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document.write( "2x-3y=-25<BR>\n" );
document.write( "3x+y=1\r<BR>\n" );
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document.write( "Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205790 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-3y=-25<BR>\n" );
document.write( "3x+y=1<BR>\n" );
document.write( "y=1-3x<BR>\n" );
document.write( "Now replace y in the first equation with (1-3x) & solve for x.<BR>\n" );
document.write( "2x-3(1-3x)=-25<BR>\n" );
document.write( "2x-3+9x=-25<BR>\n" );
document.write( "11x=-25+3<BR>\n" );
document.write( "11x=-22<BR>\n" );
document.write( "x=-22/11<BR>\n" );
document.write( "x=-2 ans.<BR>\n" );
document.write( "y=1-3*-2<BR>\n" );
document.write( "y=1+6=7 ans.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "3*-2+7=1<BR>\n" );
document.write( "-6+7=1<BR>\n" );
document.write( "1=1 </SPAN>\n" );
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