document.write( "Question 283529: two times a number plus three times another number equals 13. the sum of the two numbers is 7 \n" ); document.write( "
Algebra.Com's Answer #205789 by JenniferTutors(83)\"\" \"About 
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Two times a number: 2x
\n" ); document.write( "x = (unknown)a number
\n" ); document.write( "Two times a number plus three times another number: 2x + 3y
\n" ); document.write( "y = (unknown) another number
\n" ); document.write( "Two times a number plus three times another number equals 13:
\n" ); document.write( " 2x + 3y = 13\r
\n" ); document.write( "\n" ); document.write( "the sum of the two numbers is 7
\n" ); document.write( "\"is\" usually can refer to equals
\n" ); document.write( "the 2 unknown numbers are x & y, so:\r
\n" ); document.write( "\n" ); document.write( "x + y = 17\r
\n" ); document.write( "\n" ); document.write( "Now you have two equations: 2x + 3y = 13 & x + y = 7 \r
\n" ); document.write( "\n" ); document.write( "Here you can see that if you get one variable by itself in the second equation, you can place it into the first equation:\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+7\"
\n" ); document.write( "I have y by itself, by subtracting the x to the other side:
\n" ); document.write( "\"y+=+-x+%2B+7\"\r
\n" ); document.write( "\n" ); document.write( "Next, you can place the y into the first equation:\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+3y+=+13\"\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+3%28-x+%2B+7%29+=+13\"\r
\n" ); document.write( "\n" ); document.write( "Follow order of operations:\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+%28-3x%29+%2B+21+=+13\"
\n" ); document.write( "I don't usually like to keep my problems like this, math books usually show you this way, honestly I think it's confusing, as long as you remember to keep the negative to the 3, look below I'll rewrite it so there isn't as many positive & neg signs:
\n" ); document.write( "\"2x+-+3x+%2B+21+=+13\"\r
\n" ); document.write( "\n" ); document.write( "Next you subtract the like terms= x's :\r
\n" ); document.write( "\n" ); document.write( "\"-x+%2B+21+=+13\"\r
\n" ); document.write( "\n" ); document.write( "To get x by itself, subtract the 21 :\r
\n" ); document.write( "\n" ); document.write( "\"-x+=+-21+%2B+13\"
\n" ); document.write( "\"-x+=+-8\"\r
\n" ); document.write( "\n" ); document.write( "You cannot leave variables in the negative this way, since a variable 'x'
\n" ); document.write( "always has a one, but we usually don't write it '1x', Well to make the x positive we need to divide a negative 1 to both sides of the equation:\r
\n" ); document.write( "\n" ); document.write( "\"-x%2F-1+=+-8%2F-1\"
\n" ); document.write( "Negative/Negative equals Positive
\n" ); document.write( "\"x+=+8\" \r
\n" ); document.write( "\n" ); document.write( "Now you can place the x value into the second equation:\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+7\"
\n" ); document.write( "\"8+%2B+y+=+7\"\r
\n" ); document.write( "\n" ); document.write( "Get y by itself:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-8+%2B+7\"
\n" ); document.write( "\"y+=+-1\"\r
\n" ); document.write( "\n" ); document.write( "Now you have both of the values, x = 8, y = -1
\n" ); document.write( "To Check, place the values into the first equation:\r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+3y+=+13\"
\n" ); document.write( "\"2%288%29+%2B+3%28-1%29+=+13\"\r
\n" ); document.write( "\n" ); document.write( "\"16+-+3+=+13\"\r
\n" ); document.write( "\n" ); document.write( "\"13+=+13\" Checks out. \r
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