document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283522>Question 283522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a restaurant offers the possibility of 168 three course dinners.  Each dinner has an appetizer, an entree' and a dessert.  If the number of appetizers decreases from 7 to 5, find how many fewer possible three-course dinners the restaurant offers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205784 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a*b*c=168<BR>\n" );
document.write( "7*b*c=168<BR>\n" );
document.write( "b*c=168/7=24<BR>\n" );
document.write( "now we have<BR>\n" );
document.write( "5*24=120<BR>\n" );
document.write( "168-120=48 or 2*24<BR>\n" );
document.write( "There are 48 fewer possible three course dinners\r<BR>\n" );
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document.write( " </SPAN>\n" );
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