document.write( "Question 34303: Write and equation and solve the following problem.
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document.write( "The area or a rectangle is 130 square feet. Find the dimensions of the rectangle if the length is 3 feet greater than the width.
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document.write( "I know A=LW so: 130 = L+3 = w
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document.write( "Did I get the formula correct \n" );
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Algebra.Com's Answer #20575 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE MY COMMENTS BELOW \n" ); document.write( "The area or a rectangle is 130 square feet. Find the dimensions of the rectangle if the length is 3 feet greater than the width. \n" ); document.write( "I know A=LW....OK \n" ); document.write( " so: 130 = L+3 = w....NO....GO STEP BY STEP....LENGTH IS MORE THAN WIDTH...SO \n" ); document.write( "L=W+3...OK...NOW AREA =LW=(W+3)W=130 \n" ); document.write( "SO WE GET \n" ); document.write( "W^2+3W=130 \n" ); document.write( "W^3+3W-130=0 \n" ); document.write( "W^2+13W-10W-130=0 \n" ); document.write( "W(W+13)-10(W+13)=0 \n" ); document.write( "(W-10)(W+13)=0 \n" ); document.write( "W-10=0....OR...W=10 \n" ); document.write( "SO L=W+3=10+3=13 \n" ); document.write( "Did I get the formula correct \n" ); document.write( " |