document.write( "Question 283379: how do I factor completely:
\n" ); document.write( "4a^2 -4a -48
\n" ); document.write( "

Algebra.Com's Answer #205701 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
right away you can see that you can factor 4
\n" ); document.write( "4*(a^2-a-12)
\n" ); document.write( "now we have 1 and 12
\n" ); document.write( "so we need factors of twelve with a difference of one
\n" ); document.write( "1 12 11
\n" ); document.write( "2 6 4
\n" ); document.write( "3 4 1
\n" ); document.write( "4 3 1
\n" ); document.write( "we are repeating and the only match is 3 and 4
\n" ); document.write( "the larger number must be negative
\n" ); document.write( "(a-4)*(a+3)
\n" ); document.write( "so now we have 4*(a-4)*(a+3)
\n" ); document.write( "
\n" ); document.write( "
\n" );