document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283380>Question 283380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely.\r<BR>\n" );
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document.write( "64x^2 - 48xy + 9y^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205699 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You might guess that the first term will have an 8 and the last term will have a 3<BR>\n" );
document.write( "since 8^2=64 and 3^2=9<BR>\n" );
document.write( "But what next ? how do you get the xy?<BR>\n" );
document.write( "obviously there must be y in the second term also <BR>\n" );
document.write( "and the second term also must be negative<BR>\n" );
document.write( "so what do we know so far.<BR>\n" );
document.write( "8x is a good start for the first term<BR>\n" );
document.write( "-3y looks like it might be the second term<BR>\n" );
document.write( "since (-3y)*(-3y)=9y^2<BR>\n" );
document.write( "But will it give us the -48xy<BR>\n" );
document.write( "(8x-3y)*(8x-3y)=64x^2-24xy-24xy+9y^2<BR>\n" );
document.write( "It works since -24xy-24xy=-48xy<BR>\n" );
document.write( "So our answer is <BR>\n" );
document.write( "(8x-3y)*(8x-3y) or (8x-3y)^2 </SPAN>\n" );
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