document.write( "Question 283344: Question 1: I start with 8.I add -2 then take away -6. What do I get?\r
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document.write( "Question 2: What do you get if you add 3*-6 and -7*-10?\r
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document.write( "Answer clear and readable please. \n" );
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Algebra.Com's Answer #205683 by Theo(13342)![]() ![]() You can put this solution on YOUR website! QUESTION 1:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8 + (-2) - (-6) = 8 - 2 + 6 = 6 + 6 = 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8 + (-2) is the same as subtracting 2 from 8 to get 6.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6 - (-6) is the same as adding 6 to 6 to get 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "positive plus negative is the same as positive minus positive with the sign of the result coming from the larger operand. \n" ); document.write( "positive minus negative is the same as positive + positive with the sign of the result always being positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "QUESTION 2:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3*(-6) + (-7)*(-10) = -18 + 70 = 52.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3*(-6) will always be negative because a plus times a minus is always minus.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(-7)*(-10) will always be positive because a minus times a minus is always positive.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-18 plus 70 is the same as 70 minus 18 = 52.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "positive times negative will always be negative. \n" ); document.write( "negative times negative will always be positive. \n" ); document.write( "negative plus positive is the same as positive plus negative is the same as positive minus positive with the sign of the result coming from the larger operand.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |