document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283256>Question 283256</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother is twice as old as her daughter now, but 10 years ago, she was 3 times as<BR>\n" );
document.write( "old as her daughter. Find their ages at present. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205675 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the daughter's age be x\r<BR>\n" );
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document.write( "mother's age will be 2x\r<BR>\n" );
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document.write( "Ten years ago\r<BR>\n" );
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document.write( "daughter's age x-10\r<BR>\n" );
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document.write( "Mother's age 3(x-10)\r<BR>\n" );
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document.write( "x-10 =3(x=10)\r<BR>\n" );
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document.write( "x=10=3x-30\r<BR>\n" );
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document.write( "3x-x=10+30\r<BR>\n" );
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document.write( "2x=40\r<BR>\n" );
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document.write( "x=40/2\r<BR>\n" );
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document.write( "x=20 Daughter's age now\r<BR>\n" );
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document.write( "Mother's age is 2x = 2*20 = 40 years </SPAN>\n" );
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