document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283300>Question 283300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the product of two consecutive positive odd integers is one less than three times their sum. find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205674 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number be x\r<BR>\n" );
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document.write( "the second number will be x+2\r<BR>\n" );
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document.write( "the product will be x(x+2)\r<BR>\n" );
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document.write( " three times the sum less 1 = 3(x+x+2)-1\r<BR>\n" );
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document.write( "x(x+2)=3(2x+2)-1\r<BR>\n" );
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document.write( "x^2+2x=6x+6-1\r<BR>\n" );
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document.write( "x^2+2x-6x=+6-1\r<BR>\n" );
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document.write( "x^2-4x=+5\r<BR>\n" );
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document.write( "x^2-4x-5=0\r<BR>\n" );
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document.write( "x^2-5x+x-5=0\r<BR>\n" );
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document.write( "x(x-5)+1(x-5)=0\r<BR>\n" );
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document.write( "(x+1)(x-5)=0\r<BR>\n" );
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document.write( "x=-1 or 5  \r<BR>\n" );
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document.write( "So 5 & 7 are the numbers </SPAN>\n" );
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