document.write( "Question 283317: What is the perimeter and area of the rectangle the top side is 3+6 times the square root of 2 yards and the right side is the square root of 8 yards. \n" ); document.write( "
Algebra.Com's Answer #205670 by mananth(16946)\"\" \"About 
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What is the perimeter and area of the rectangle the top side is 3+6 times the square root of 2 yards and the right side is the square root of 8 yards.\r
\n" ); document.write( "\n" ); document.write( "length = 3+6sqrt2\r
\n" ); document.write( "\n" ); document.write( "width= sqrt8\r
\n" ); document.write( "\n" ); document.write( "perimeter = 2(3+6sqrt2) + 2 (sqrt8)\r
\n" ); document.write( "\n" ); document.write( "= 6+12sqrt2+2sqrt8\r
\n" ); document.write( "\n" ); document.write( "=6+12sqrt2+2*2 sqrt2----------------- 2sqrt8 = 2sqrt (2*4)=2sqrt2*sqrt4 =4sqrt2\r
\n" ); document.write( "\n" ); document.write( "=6+12sqrt2+4sqrt2\r
\n" ); document.write( "\n" ); document.write( "=6+16sqrt2 yards = perimeter\r
\n" ); document.write( "\n" ); document.write( "Area = L*W\r
\n" ); document.write( "\n" ); document.write( "= (3+6sqrt2)*2sqrt8
\n" ); document.write( "=(3+6sqrt2)*4sqrt2
\n" ); document.write( "=4sqrt2 +24sqrt2
\n" ); document.write( "=28sqrt2 square yards is the area\r
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