document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283306>Question 283306</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2y^(2/3)+17y^(1/3)+30=0\r<BR>\n" );
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document.write( "I don't understand how to do this problem!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205654 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205654\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y^(2/3)+17y^(1/3)+30=0<BR>\n" );
document.write( "let y^(1/3)=u<BR>\n" );
document.write( "2u^2+17u+30=0\r<BR>\n" );
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document.write( "(u+6) (2 u+5) = 0<BR>\n" );
document.write( "plug y^(1/3) back in for u<BR>\n" );
document.write( "(y^(1/3)+6)*(2y^(1/3)+5)=0\r<BR>\n" );
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document.write( "(y^(1/3)+6)=0<BR>\n" );
document.write( "y^(1/3)=-6<BR>\n" );
document.write( "y=(-6)^3<BR>\n" );
document.write( "(2y^(1/3)+5)=0<BR>\n" );
document.write( "2y^(2/3)=-5<BR>\n" );
document.write( "y^(2/3)=-5/2<BR>\n" );
document.write( "y^2=(-5/2)^3<BR>\n" );
document.write( "y^2 = -125/8<BR>\n" );
document.write( "y=sqrt(-125/8)<BR>\n" );
document.write( "y=-sqrt(-125/8)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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