document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=34286>Question 34286</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0321227573/algebrahomeworkh>college algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 1. x=8log100(10)    \r<BR>\n" );
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document.write( "Next two need to be written as a single expression with coefficient.<BR>\n" );
document.write( "2. logaK-logbM-logbA\r<BR>\n" );
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document.write( "3. logb(2y+5)-1/2logb(y+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #20561 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=20561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log10 using base of 100 = (1/2)<BR>\n" );
document.write( "That means 100^(1/2)=10<BR>\n" );
document.write( "Your problem becomes <BR>\n" );
document.write( "x=8(1/2)=4\r<BR>\n" );
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document.write( "=logaK-(logM + logbA)<BR>\n" );
document.write( "=loaK-(logb(MA))\r<BR>\n" );
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document.write( "=logb(2y+3) - logb(y+3)^(1/2)<BR>\n" );
document.write( "=logb[(2y+3)/sqrt(y+3)]<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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