document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283151>Question 283151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of rectangle is 800 yards. what are the dimenision of the rectangle if the length is 10 yards more than the width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205587 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=PERIMETER<BR>\n" );
document.write( "L=W+10<BR>\n" );
document.write( "2(W+10)+2W=800<BR>\n" );
document.write( "2W+20+2W=800<BR>\n" );
document.write( "4W=800-20<BR>\n" );
document.write( "4W=780<BR>\n" );
document.write( "W=780/4<BR>\n" );
document.write( "W=195 YDS. IS THE WIDTH.<BR>\n" );
document.write( "L=195+10=205 YDS. IS THE LENGTH. pROOF:<BR>\n" );
document.write( "2*205+2*195=800<BR>\n" );
document.write( "410+390=800<BR>\n" );
document.write( "800=800 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );