document.write( "Question 283131: 3x-2y=10, 2x+3y=-2 by substitution \n" ); document.write( "
Algebra.Com's Answer #205543 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
substitution is the harder way to go. This was made for elimination or subtraction/addition\r
\n" ); document.write( "\n" ); document.write( "3x-2y=10
\n" ); document.write( "2x+3y=-2
\n" ); document.write( "First by elimination or addition
\n" ); document.write( "multiply first by 3 and second by 2
\n" ); document.write( "9x-6y=30
\n" ); document.write( "4x+6y=-4
\n" ); document.write( "add
\n" ); document.write( "13x=26
\n" ); document.write( "x=2
\n" ); document.write( "2x+3y=-2
\n" ); document.write( "4+3y=-2
\n" ); document.write( "3y=-6
\n" ); document.write( "y=-2
\n" ); document.write( "(2,-2)
\n" ); document.write( "now by substitution
\n" ); document.write( "3x-2y=10
\n" ); document.write( "2x+3y=-2
\n" ); document.write( "solve first for x
\n" ); document.write( "3x=10+2y
\n" ); document.write( "x=10/3+2y/3
\n" ); document.write( "plug it in the second
\n" ); document.write( "2*(10/3+2y/3)+3y=-2
\n" ); document.write( "20/3+4y/3+3y=-2
\n" ); document.write( "multiply by 3
\n" ); document.write( "20+4y+9y=-6
\n" ); document.write( "13y=-26
\n" ); document.write( "y=-2
\n" ); document.write( "plug it in any equation and solve for x
\n" ); document.write( "3x-2y=10
\n" ); document.write( "3x-2*(-2)=10
\n" ); document.write( "3x+4=10
\n" ); document.write( "3x=6
\n" ); document.write( "x=2
\n" ); document.write( " \n" ); document.write( "
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