document.write( "Question 283099: A boxing ring is in the shape of a square, 20 feet on each side. How far apart are the fighters when they are in opposite corners of the ring? \n" ); document.write( "

Algebra.Com's Answer #205527 by Earlsdon(6294) $\"\"$ $\"About$

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The answer entails finding the length of the diagonal of the square \"ring\" which is easily accomlished using the Pythagorean theorem $\"c%5E2+=+a%5E2%2Bb%5E2\"$ .
\n" ); document.write( "Here, a & b (the lengths of the sides of the square) = 20 feet each and c will be the length of the diagonal and thus the distance separating the two boxers when they are in their respective corners.
\n" ); document.write( " $\"c%5E2+=+a%5E2%2Bb%5E2\"$ Substitute a = 20 and b = 20.
\n" ); document.write( " $\"c%5E2+=+20%5E2%2B20%5E2\"$
\n" ); document.write( " $\"c%5E2+=+400%2B400\"$
\n" ); document.write( " $\"c%5E2+=+800\"$ Take the square root of both sides.
\n" ); document.write( " $\"c+=+sqrt%28800%29\"$
\n" ); document.write( " $\"c+=+28.28\"$ feet.
\n" ); document.write( "The boxers are 28.28 feet apart. \n" ); document.write( "

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