document.write( "Question 283104: rearranging equations\r
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document.write( "make x the subjects of:
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document.write( "x-y=w
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document.write( "x+3y=5v
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document.write( "v2+x=w
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document.write( "5v+x=w
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document.write( "x2=6y
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document.write( "x2+v=w
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document.write( "x2/7=w-y
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document.write( "x2+6/w=y
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document.write( "x/y+7=v
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document.write( "v/5x=w/y
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document.write( "vx-w=6
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document.write( "5w2+vx=y
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document.write( "a(x+b)=c or x=something/something
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document.write( "6(x+a)=b or x=something/something
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document.write( "a(x-5)=b or x=something/something
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document.write( "c(6+x)=5 or x=something/something\r
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document.write( "I want both solutions for the last 4 questions. \n" );
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Algebra.Com's Answer #205526 by dabanfield(803)![]() ![]() ![]() You can put this solution on YOUR website! 1.)a(x+b)=c or x=something/something \n" ); document.write( "2.)6(x+a)=b or x=something/something \n" ); document.write( "3.)a(x-5)=b or x=something/something \n" ); document.write( "4.)c(6+x)=5 or x=something/something \n" ); document.write( "I want both solutions for the last 4 questions.\r \n" ); document.write( "\n" ); document.write( "Using the distributive property:\r \n" ); document.write( "\n" ); document.write( "1.) a(x+b) = c \n" ); document.write( "ax+ab = c \n" ); document.write( "ax = c-ab \n" ); document.write( "x = (c-ab)/a\r \n" ); document.write( "\n" ); document.write( "2.) 6(x-a) = b \n" ); document.write( "6x -6a = b \n" ); document.write( "6x = b+6a \n" ); document.write( "x = (b+6a)/6\r \n" ); document.write( "\n" ); document.write( "The last two are similar.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |