document.write( "Question 283089: I feel stupid asking this. I'm just starting to work on these?
\n" ); document.write( "The problem I got is
\n" ); document.write( "log2y=3\r
\n" ); document.write( "\n" ); document.write( "Now if I'm correct, I try to find x and convert this to\r
\n" ); document.write( "\n" ); document.write( "y=log(2)3\r
\n" ); document.write( "\n" ); document.write( "In which case, is it no solution?
\n" ); document.write( "Or am I completely off in how I'm working on these?
\n" ); document.write( "Thanks,
\n" ); document.write( "Nathalie
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Algebra.Com's Answer #205511 by nabla(475)\"\" \"About 
You can put this solution on YOUR website!
Is that a log of base 2? By definition log_2(y)=3 means 2^3=y implies 8=y.\r
\n" ); document.write( "\n" ); document.write( "In words, the base of a log to the power of the other side of the equation is equal to what the log was of (this may be confusing and it certainly is not concise).
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