document.write( "Question 283074: A fence encloses a square yard with an area of 36 m^2. The same amount of fencing can enclose a rectangular yard whose width is 2/3 the width of the square. What is the area of the rectangle?\r
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document.write( "a) 24 b) 32 c) 48 d) 64 e) can not be determined
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Algebra.Com's Answer #205484 by mananth(16946)![]() ![]() You can put this solution on YOUR website! area of aquare =36 \r \n" ); document.write( "\n" ); document.write( "so width of square =6\r \n" ); document.write( "\n" ); document.write( "The perimeter of the square = 6*4=24\r \n" ); document.write( "\n" ); document.write( "the width of rectangle is 2/3 of width of square = 2/3*6 =4m\r \n" ); document.write( "\n" ); document.write( "let length of rectangle be x\r \n" ); document.write( "\n" ); document.write( "2x+8 =24 (perimeter of square and rectangle is same)\r \n" ); document.write( "\n" ); document.write( "2x=24-8\r \n" ); document.write( "\n" ); document.write( "2x=16 \n" ); document.write( "x=16/2 \n" ); document.write( "x=8 m \n" ); document.write( "The length of rectangle = 8 and width =4.\r \n" ); document.write( "\n" ); document.write( "so area = 32square meters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |