document.write( "Question 283042: The product of two positive consecutive integers is 41 more than their sum. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #205473 by MathTherapy(10552)\"\" \"About 
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The product of two positive consecutive integers is 41 more than their sum. Find the integers.\r
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\n" ); document.write( "\n" ); document.write( "Let the first number be F\r
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\n" ); document.write( "\n" ); document.write( "Then the second = F + 1\r
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\n" ); document.write( "\n" ); document.write( "Their product = F(F + 1) = \"F%5E2+%2B+F\", and their sum is: F + F + 1 = 2F + 1\r
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\n" ); document.write( "Since their product is 41 more than their sum, then we have:\r
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\n" ); document.write( "\n" ); document.write( "\"F%5E2+%2B+F+=+2F+%2B+1+%2B+41\"\r
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\n" ); document.write( "\n" ); document.write( "\"F%5E2+-+F+-+42+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "(F + 6)(F - 7) = 0\r
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\n" ); document.write( "\n" ); document.write( "Ignore F + 6 = 0, because F = - 6, and we're looking for a positive number. Therefore, F, or the 1st number is 7, and so, the numbers are \"highlight_green%287_and_8%29\"
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