document.write( "Question 283042: The product of two positive consecutive integers is 41 more than their sum. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #205473 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! The product of two positive consecutive integers is 41 more than their sum. Find the integers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the first number be F\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then the second = F + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Their product = F(F + 1) = \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Since their product is 41 more than their sum, then we have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(F + 6)(F - 7) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Ignore F + 6 = 0, because F = - 6, and we're looking for a positive number. Therefore, F, or the 1st number is 7, and so, the numbers are |