document.write( "Question 282952: a man bicycles 5 mph faster than he walks. He bicycles 24 miles and then hikes back along the same route in 11 hours. How fast does he walk? \n" ); document.write( "
Algebra.Com's Answer #205470 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! a man bicycles 5 mph faster than he walks. He bicycles 24 miles and then hikes back along the same route in 11 hours. How fast does he walk?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let the speed that he walks be W. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then the speed that he bikes at is W + 5, since he bikes 5 mph faster than he walks\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "His time to walk 24 miles (end leg of trip) would then be: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since he does both ends of the trip in 11 hours, then we'll have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(11W + 40)(W - 3) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "11W = - 40 (ignore, as speed CANNOT be a negative value)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, W, or his walking speed = |