document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=283015>Question 283015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: 1-3c=9c+7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205454 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "The key to solving an equation is getting the variable (in this case, \"c\") all by itself on one side of the equal sign.<BR>\n" );
document.write( "1-3c=9c+7 Add 3c to both sides to get:<BR>\n" );
document.write( "1=12c+7 Now subtract 7 from both sides to get:<BR>\n" );
document.write( "-6=12c Now the last step is to divide both sides by 12 to result in:<BR>\n" );
document.write( "c=-1/2<BR>\n" );
document.write( "Plug this answer into the original to see if it works. <BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "There's a book I wrote that will help you out. <BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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