document.write( "Question 282957: Factor by grouping...8a^3 - 2a^2 + 12a - 3 \n" ); document.write( "
Algebra.Com's Answer #205424 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 8a^3 - 2a^2 + 12a - 3 \n" ); document.write( "(8a^3 - 2a^2) + (12a - 3) \n" ); document.write( "2a^2*(4a-1)+3*(4a-1) \n" ); document.write( "(2a^2+3)*(4a-1) \n" ); document.write( " |