document.write( "Question 282914: 1. x2-2x-24 2. x2+3x-10 (two problems)x2 is little 2 after an uphigh on x.. (how to do problems) Complete the square for the following quadratic polynomials (that is, express in the form(x + _)2 + _ where you fill in the blanks with numbers). (x+ _)2 is little 2 after ). \n" ); document.write( "
Algebra.Com's Answer #205388 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to show you how to do these problems.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x-24\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"-2\" to get \"-1\". In other words, \"%281%2F2%29%28-2%29=-1\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"-1\" to get \"1\". In other words, \"%28-1%29%5E2=%28-1%29%28-1%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2Bhighlight%281-1%29-24\" Now add and subtract \"1\". Make sure to place this after the \"x\" term. Notice how \"1-1=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-2x%2B1%29-1-24\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2-1-24\" Factor \"x%5E2-2x%2B1\" to get \"%28x-1%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2-25\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"x%5E2-2x-24\" transforms to \"%28x-1%29%5E2-25\". \r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2-2x-24=%28x-1%29%5E2-25\".\r
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