document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282899>Question 282899</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having problems trying to figure this problem. I am not sure if I have to multiply the diagonal meter by the lengths of the sides.\r<BR>\n" );
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document.write( "One side of a rectangular stage is 2 meters longer than the other. If the diagonal is 10 meters, then what are the lengths of the sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205352 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+(x+2)^2=10^2\r<BR>\n" );
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document.write( "x^2+x^2+4x+4=100\r<BR>\n" );
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document.write( "2x^2+4x-96=0\r<BR>\n" );
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document.write( "x^2+2x-48=0\r<BR>\n" );
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document.write( "(x-6)(x+8)=0\r<BR>\n" );
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document.write( "x-6=0 or x+8=0\r<BR>\n" );
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document.write( "x=6 or x=8\r<BR>\n" );
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document.write( "Answer: side lengths are 6 and 8 </SPAN>\n" );
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