document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=282783>Question 282783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle of diameter 6 in. has its center at the center of a square of side 6 in. Find the area of the region that is inside the square and outside the circle.\r<BR>\n" );
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document.write( "a. (36&#960; - 36) in.2 b. (36 - 6&#960;) in.2 c. (36 - 9&#960;) in.2 d. (9&#960; - 36) in.2 e. None of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #205292 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=205292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A circle of diameter 6 in. has its center at the center of a square of side 6 in. Find the area of the region that is inside the square and outside the circle.<BR>\n" );
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document.write( "It's the area of the square ( = 6*6)<BR>\n" );
document.write( "minus the area of the circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A3%5E2 ALIGN=MIDDLE  ALT=\"pi%2A3%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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